#I don't know where it should go or if I'm going the wrong way
85 messages · Page 1 of 1 (latest)
|a|<1 implies that -1<a<1
ok so
is it correct that i develop the first one i think that's the word for it
because what i do is
caso 1 or case 1
i make it so i solve that one
-3x < 2x+3-2 then
-3x-2x< 1 no?
and then -5x < 1
is that it?
at least for case 1
WAIT im doing it another way aren't i
sorry
is that better or easier than what i was trying-
wait uhmmm
ok
let me try what you said
You can't cross product because you don't know the sign of the expression that you're multiplying by
what is cross product
You multiplied by 2x+3 right?
but if they're absolute value it would it not be the same?
wait ok
sign, right
this this, how do i try this
Do you know the sign table btw
ok so im thinking
it's likeeee
uh in this case
i don't think i know
but i know what IT is
So basically
2x-3 equals 0 if x=3/2 right?
You take a number before 3/2 for example 1 plug in 1 in 2x-3
We get -1 therefore every number before 3/2 makes our expression negative right?
ok yeah i know how that works
but
then
just 2x-3?
wait
both of them?
2x+3 and 2-3x?
a lil confusing but
like numerator and denominator?
cuz it would be -3/2 instead
so then if i take 1 it would be positive if it's 2x+3
but like what equations am i inputing in for the table
Forget this thing we can do something easier
alr sorry
okayyy
Yes
Now it is easy
Just square both sites and some simple algebra you will get a simple inequality
oh oh and it wouldn't flip anything since it's
always positive right?
let me try that
Absolutely
WHAT this brought me to the answer i already had
but hey i have a new way of doing it
it left me to
-1/5 < x < 5
so, yeah
that
ill look into trying the sign table cuz that also seems faster
That's what i got too
If somehow you found a mistake just pardon me because it's 3am
OH THAT'S OKAY
