#Prime power
6 messages · Page 1 of 1 (latest)
6 messages · Page 1 of 1 (latest)
is it true that: if we have number x^n where n - any prime number, there's no number y^z where z >1 that will be equal to x^n? also all numbers are natural
ig it was stupid question
I found a counter example
Consider 8^2=64
2^6=64