#how do i do the derivative of this
4 messages · Page 1 of 1 (latest)
yes it is y'
and the formula for the derivative of $\sqrt{u}$ is
$\frac{u'}{2\sqrt{u}}$
where u is a function
4 messages · Page 1 of 1 (latest)
yes it is y'
and the formula for the derivative of $\sqrt{u}$ is
$\frac{u'}{2\sqrt{u}}$
where u is a function