#sin(12x)/sin(5x)
12 messages · Page 1 of 1 (latest)
It is better to say there's a break in the curve
while plotting we consider exact values
by using limit you can decide where the curve tends to go if x appoaches 0
but you can't exactly plot it at x=0
So stick with the undefined then?
yeah you just doesn't plot any point at exact x=0
Got it, thanks!
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