Year 4 question and explanation

[pine idol]

I’m actually confused how you would work this out.

During a 5-day tennis competition, crowd numbers fluctuated between a low of 122 on Day 1 and a high of 455 on the last day. If the average daily attendance for the other days was 341, what is the average daily attendance rate for the whole competition?

[stone copper]

We have 5 days: D1, D2, D3, D4, D5. We know that the crowd number for D1 is 122 and 455 for D5. The average daily attendance of the other days (meaning D2, D3, D4) is 341 which means that:

(D2 + D3 + D4)/3 = 341

Therefore

D2 + D3 + D4 = 1023

The average daily attendance for the whole competition is given by:

(D1 + D2 + D3 + D4 + D5)/5 = x

Since D2 + D3 + D4 = 1023 & D1 + D5 = 122 + 455 = 577, then D1 + D2 + D3 + D4 + D5 = 1023 + 577 = 1600. So by substitution we have:

x = 1600/5 = 320

@pine idol

[pine idol]

Ahhh you’re so right

Thank you so much

[stone copper]

You're welcome

[fresh trellis]

!nosols

[feral umbra]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.