#Find equation of plane given curve
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x_Shadow_x
$\underline{\gamma}(t)=(\ell cos(t), \ell sin(t), sin(kt))$
x_Shadow_x
To look at it better
Couldn’t you just substitute different values of T to get three different points
and then find the plane using the normal vector
I can try thx, but isn't there another method?
I’m not sure, this is something I’m familiar with
I graphed it and it doesn’t actually seem to be contained in a plane unless k=0
oh
this is an exercise from a quiz, and the result says:
"the curve lies always on the cylindric surface [...], lies on the plane {y-lz=0} if and only if k=1, ..."
That makes sense because lcost, lsint parameterises a circle in the xy plane
I can’t help u with figuring out y-lz=0 but it makes sense in retrospect
yeah it seems right thinking about it but I don't know the quick procedure to obtain it... anyway thank you!