limit x->5 1/(x-5)

[vague bobcat]

Is this even possible?

[stone torrent]

+infinity if x approching 5 by being greater than 5

and -infinity if x approching 5 by being less than 5

$\lim_{x \to 5^{+}} \frac{1}{x-5} = +\infty$

$\lim_{x \to 5^{-}} \frac{1}{x-5} = -\infty$

$\lim_{x \to 5} \frac{1}{x-5}$ doesn't exist since we have different result depending on where x is on the real axis

[left night]

un_decorateur

[vague bobcat]

Ahh got it thanks!

[stone torrent]

!done

[light basin]

If you are done with this channel, please mark your problem as solved by typing .close

[vague bobcat]

.close