Help (module)

[knotty nova]

I could only find x1 and x2 its 4;9

[faint sonnet]

Can you explain what you are trying to say

[weak shore]

The solution should be an interval no?

[sacred sigil]

𝔸dωn𝓲²s

[weak shore]

1s case consider x-√x +1 >0
Then you can remove absoulute value
And simplify things you should get this
(x-4)(x-3) -2√x(x-4)>0
Common factor (x-4)
(x-4)(x-3-2√x)>0
Now consider when they're both positive and when they're negative and solve for x
Then do the same to our second case x -√x +1<0

[knotty nova]

i solved 1s case with >

I couldn't get an answer from <0

the first time I solved the equation of 4 degrees with substitution and got the roots 4 and 9, but the second time it did not work out where <0

oh, maybe i found my error

or no

[knotty nova]

yea

i need to get this answer

[weak shore]

Second case isn't possible
Because x-√x can be negative but will never be less or equal to -1

[knotty nova]

then I initially did everything right) I just thought in 2 cases I'm doing something wrong

thank you

[sand slate]

.close