#Number theory question

26 messages · Page 1 of 1 (latest)

raw elm
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This is something i am just curios about. I had observed this a few months ago but could not make progress. The problem is that to find a general form of square numbers whose sum of their divisors are also square numbers. An example of this would be 81. The sum of 81's divisors is 121 which is a square.

wispy mulchBOT
broken chasm
raw elm
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So you are saying :-
Let $n = {p_1}^{d_1} {p_2}^{d_2} ................ {p_k}^{d_k}$.
So we can write $\sigma(n^2) = \sigma ({p_1}^{2d_1} {p_2}^{2d_2} ……………. {p_k}^{2d_k})$

median karmaBOT
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Someone_Random

broken chasm
raw elm
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oh ok

raw elm
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I dont seem to find a pattern in the numbers that satisfy this condition

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a sequncefrom this series is 1 , 81 ,400 , 32400 , 1705636 ,3648100

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or 1 , 9 , 20 , 180 , 1306 , 1910

raw elm
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?

broken chasm
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Hmmmm

raw elm
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I cannot see a pattern

broken chasm
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My thought now is to remove the original condition that the sum of numbers not just square numbers is a perfect square il check numbers and try to devise something and update you then we can add the original condition and see what new happens

raw elm
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oh good idea

broken chasm
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Rn I'm unable to identify a pattern il advice you to ask the seniors here they'll guide you better ig

raw elm
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sure

wild vigil
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This problem feels open

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You're looking for all squares of the form
[\prod_{i=1}^k\left(1+p_i+p_i^2+\dots+p_i^{2a_i}\right)]
where $p_1,p_2,\dots,p_k$ are distinct primes and $a_1,a_2,\dots,a_k$ are positive integers.

median karmaBOT
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Daniel

wild vigil
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That seems intractable

raw elm
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what do you mean?

wild vigil
raw elm
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tru

lavish kelp
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.close