HCF and LCM

[flat pond]

I got 5 as the answer

I eliminated quite a bit of numbers simply bh seeing the options

@nocturne nimbus

[nocturne nimbus]

The problem is 8 and 3 are also satisfying the equation

[flat pond]

n can't be 12 since the largest solution was 11

[nocturne nimbus]

Bro 8 is x and 3 is y

You can ✅ check. It satisfies

[flat pond]

Bruh thats wrong

Plug that into the equation 32xyn=x^6 y^2

We know y=n

32x=x^6

32x8=x^6

So

X becomes 2^(4/3)

Which is wrong since then x won't be natural

@nocturne nimbus

[nocturne nimbus]

It's not

[nocturne nimbus]

I didn't see your equation. Plug it in my equation.

The one given in question and it'll satisfy

I just saw your solution in a cursorily manner

[nocturne nimbus]

Actually you're equating 2⁵ with x⁵ which isn't wrong but it isn't true always because 32 doesn't necessarily have to be as it is in x⁵y, it can also be a factor of x⁵y which is basically the whole point of HCF

And that's why 8 and 3 satisfy the equation

[flat pond]

Nope

[nocturne nimbus]

I'll prove you wrong. Wait

[flat pond]

32xyn=x^6 y^2
Y=n
So 32x=x^6
32=x^5
Where does 8 come.8 doesn't satisfy it at all

[nocturne nimbus]

You're hyperfixated on your solution

[nocturne nimbus]

See! No contradiction

[flat pond]

Okay lets assume x=8 y=3

That would mean that m=n=1

[nocturne nimbus]

32=x⁵
x doesn't necessarily have to be 2. You just don't get it. When we take HCF of 96 and 32, you really think there will be nothing left after removing the hcf? If we divide 96 by HCF we'll be left with 3. It's just an example to show that it's not always true

[nocturne nimbus]

Just show me the mistake here.

That's it

[flat pond]

Therefore 768=x^6 y^2
Which doesn't match with what you send

[nocturne nimbus]

Bro ur solution is wrong and only partially true

[nocturne nimbus]

I've actually shown you here

It's perfectly matching

[nocturne nimbus]

It only takes into account one case not all

[flat pond]

Nope.

We have been told that 32xy is the HCF

Therefore 32xy *m=768

[nocturne nimbus]

32xy is the HCF. You can see the theorem look clearly

Bro don't bring your m and n here

[flat pond]

Yes it is

[flat pond]

Bruh that's literally the definition

Hcf is the highest common factor

So 32xy *m=768 is factually correct

[nocturne nimbus]

You're already saying the obvious point

[nocturne nimbus]

m is 1 what's your problem

[flat pond]

So u agree with me on that?

That ur solution would mean that m=1

[nocturne nimbus]

m is 1 but 8 and 3 is also the right answer

[flat pond]

Alright lets assume m=1

[nocturne nimbus]

I'll talk about your solution later on

[nocturne nimbus]

First tell me what's wrong here. Then we'll proceed, otherwise I'm not gonna talk😭

[flat pond]

I think you are correct.
Since 32xy is the hcf
You simply equated, 32xy=768 and got x=8 and y=3
You solution is correct

[flat pond]

What did the sir say

Did he say 11 is the correct solution

Cuz 11 seems to be correct since it follows all the conditions properly

5 is wrong

[flat pond]

@nocturne nimbus Your solution is 100% correct.There is no doubt about since the highest possible hcf of any random numbers of a,b can either be a or b depending on which is larger.

[nocturne nimbus]

No it's not wrong

[flat pond]

Lol it is

You literally proved that 768 is the highest hcf that can be derived

[nocturne nimbus]

Yeah he said, apparently he forgot that 5 is also right

[flat pond]

Fair

[nocturne nimbus]

No but there can he two possibilities. I mean both are different case and different numbers

x and y are variables so different values will give different possibilities.

[flat pond]

Yeah

[slim shoal]

.close