#Don't understand why I got the answer.
44 messages · Page 1 of 1 (latest)
,align&\int_{0}^{1}\sqrt{1+\left(\frac{d}{dx}\frac{2}{3}x^{\frac{3}{2}}\right)^{2}}dx
\=&\int_{0}^{1}\sqrt{1+\left(x^{\frac{1}{2}}\right)^{2}}dx
\=&\int_{0}^{1}\sqrt{1+x}dx
\=&\frac{2}{3}\left(1+1\right)^{\frac{3}{2}}-\frac{2}{3}\left(1+0\right)^{\frac{3}{2}}
\=&\frac{4\sqrt{2}-2}{3}
mtt
you shouldnt deviate from these steps here
what you wrote here does not mean what you think it means
same thing here, since "plugging the original equation back in" does not say where or when you did it, there are multiple correct places in the work where this can be done
therefore you havent showed or explained any work of what youve actually done
I understand everything except this part.
the integral of sqrt(x) is 2/3 x^(3/2)
so the integral of sqrt(x+1) is 2/3 (x+1)^(3/2)
I know how we get there, I just can't wrap my head around how to solve this specifically.
Like at all.
do you mean the step to get there, or how to simplify that?
you need to screenshot two lines at a time to show which step youre stuck on
How to simplify it.
so where did you get this from?
Ended up using an online calculator because of the due date, but been trying to figure out how to get it.
I got all the steps to get to the final part.
Is the simplification part that messes me up.
Especifically this one.
dont make up words like especifically please
doing this step by step,
what would be simplified first
thats not correct
Well -2/3
then what can you simplify next
I can factor out the 2/3.
Then do the inside of 1+1=2.
that 3/2 there is an improper fraction
the next step youd do here is this:
now do you see a way to go from here?
Yeah makes sense now. Just need to separate the 2 because I can write it as 2^1*2^1/2.
End up with 2*2^1/2 (or square root)-1, and distribute the 2/3 to everything.
correct
Alright thanks a lot, it makes more sense now. Didn't knew that you could just separate improper fractions like that.
np
.solved