#Interval of Continuity
242 messages · Page 1 of 1 (latest)
Continuity is simply where the function is defined it's like asking does something exist at point x
Here you're being asked to define the interval of where x is continuous and you have to identify what the graph is telling you
The circles are holes where x is not defined
so whats not the circles
Yes but what does it mean if there is a circle and full circle on the same x value
Is it still defined at this point?
like the dark one
isnt the open one like it isnt actually that point
and the dark one the absolute
Yeah open circle means it's undefined and a closed or dark circle means it's defined at that point
so do i list the dark circles?
hm i tried putting the coordinates for the dark circles
but that didnt work out
hmm
It's not asking for coordinates it's asking for intervals
The question is asking where is x continuous on the graph
So you need to give it a domain of where x exists
Have you learned interval notation yet or does that not sound familiar
probably a while ago like months i havent done math in a while
That's fine I can teach it to you quick
ok epic
Interval notation is just a fancy way of giving the set of points where a function exists
ye
The functions you're familiar with like y=x always continuous and has the interval notation of (-∞, ∞)
ye i seen those
" (" denotes that it goes up to but does not include because you can't reach infinity
so u can see better
Let's say we had a function that existed between x=-10 and x=10 we would give it the interval of [-10,10]
"[" denotes that it goes up to and includes 10
You just have to ask yourself does this include the point or not
Can you tell me the first interval to look at
It's not just the closed circles we have to at it's the open circles
Is the function defined at 0?
no
In internal notation we always start lowest than highest
That's right but why did you pick ( instead of [
doesnt include 0 or 1
Okay perfect what's your next interval
oh snap i see (1,2) but also there is a dark circle too so idk what to do witht hat one
Well we know that it starts at (1,
We just have to ask ourselves if x is defined at 2
Does f(2) exist?
That line and dot is the same function
dang then how do we decide
cause with those 2 points it looks defined and undefined
Well it's not defined at the first open circle but it is defined in the other
Since the function is defined that means x does exist
You can think of the open circle as saying the function doesn't exist there but can still exist if told otherwise
Yeah let's keep going
[2,3]?
That's right you're using the same logic
and then [3,4)
Yes put them all together and then we wills simplify
(0,1),(1,2],[2,3],[3,4)
Since (1,2],[2,3],[3,4) have touching brackets we can just combine them
Can you explain why we can do this
Yep and we can continue with (1,2],[2,4)
Yeah what's your final answer
(1,4)
And
Close
You made a small typo going from here
To here
Alright give that answer a shot if you think it's right
?
You can submit that answer lol
oh i did what in the world they had the right one as the long one lol
make sit easier i guess one second
Lol oops maybe we should done the long one
Wasn't sure if they simplified
But now you should know how to do interval notation and more
new ine
one
i got
(0,1),(1,2],[2,3],[3,4)
does that seem right
i think they want me to simplify a little
Uh I guess it wants each of the lines
that's not continuity my guy 💀
Damn I'm scammed this dude 😭
it's just being defined
$f(x) = \begin{cases}1 \text{ if }x =0 \ 0 \text{ if } x\neq 0\end{cases}$
artemetra
this function is defined for all real x but is not continuous
Looks like it ignores the full circle if it isn't connected to the function. Think of continuity instead if you can draw a line from each interval with a pencil
think of continuity around some point as having very close values to that point if you go left or right
in this case, the answer key writes (1,2) instead of (1,2] is because there is a discontinuity right at x=2
unshaded circle = not defined
shaded circle = defined to be exactly that and not where the unshaded circle is
so which one do i listen to
(0,1) is not defined here, sorry
i looked at the wrong graph
ok
(1,2) is right tho
so is it only whats on the line
what about the other line
is it (2,3) or (2,3]? let's break it down
if you look at the graph to the immediate left of x=3, you can see that the function gets closer and closer to y=3. however, AT x=3, y=2 (cuz shaded circle). so there's a sudden jump → discontinuity
which means that the correct interval is (2,3), the one excluding the 3
yeah that's right!
ok lemme see
ye
dang
wait why it say wrong on the site RIP
didi i miss something
doesn't look like it
i won't tell you the full answer but I'll say it's A
what value should go in the box there?
see
thats what i was wondering
i mean
whats teh continuous part
cause ik it stops
so is it
like
right before the definite
?
idk
this question is basically asking you to find an interval like "(a, b]"
yes!
why
well see i thought it was because it went right from there and the 4 was definite n stuff but apperantly it is not 3 
it is 4
is it because the 3 isnt real
ok
now it asksa
the same
but from the right
is it
there are none
i dont see any definite
correct
no problem!
if you are done, type ".solved"
.solved