Can anyone check the solution of this integral problem

[meager locust]

So I tried to solve this on my own. Is this correct? Can I add C on both LHS and RHS?

[meager locust]

<@&286206848099549185>

[humble lava]

When you integrate both sides then you either have to define two different constants on both sides, say $C_1$ and $C_2$. If you now subtract for example $C_1$ on both sides you get $C_2 - C_1$ on one side which can also be defined as a new constant $C := C_2 - C_1$.
So that gives us also the alternative in case of integrating both sides that one constant is enough instant of two. But if you want to have a constant on both sides respectively then they must be different, you can't define both as $C$ and subtract them as you did.

[wanton copper]

𝔸dωn𝓲²s

[meager locust]

Thanks a lot for the reply. This makes sense. I’ll make the correction

[quiet scroll]

.close