pls help its driving me insane i can't manage to figure out why c is being multiplied to x and not added
#why does solving this diffy q xy'-2y=0 equal to y=cx^2?
jagged ibex
violet parcelBOT
cursive elk
y'=2y/x
1/2y y' = 1/x
ln(y)=2ln(x)+c
y=e^{2lnx+c}
=e^{2lnx} * e^c = x^2 * e^c
call e^c a new constant C
so you have Cx^2
jagged ibex
y'=2y/x
1/2y y' = 1/x
ln(y)=2ln(x)+c
y=e^{2lnx+c}
=e^{2lnx} * e^c = x^2 * e^c
c...
oh..
didn't know you could call it a constant C after you simplify
jagged ibex
y'=2y/x
1/2y y' = 1/x
ln(y)=2ln(x)+c
y=e^{2lnx+c}
=e^{2lnx} * e^c = x^2 * e^c
c...
thank you so much greatly appreciate your help
jagged ibex
e^{constant} is always a constant so you can just rebrand it
again thank you so much! such a live saver for pointing that out to me
sudden lodge
.solved