#question on series
100 messages · Page 1 of 1 (latest)
no
you have the backwards
you have it backwards*
sorry
also they have to decrease exponentially to 0
i think the statement you are looking has the word monotonically instead of exponentially
the Σ1/n² is convergent
but 1/n² doesn't exponentially decrease
but the reciprocal statement
if a sequence has an exponential decreasing , so its series converges
? 1/n^2 does exponentially decrease
no it doesnt
it monotonically decreases
exponentially decreases would be something like (1/2)^n
You literally just wrote the same equation
1/2^n = (1/2)^n
yes
(1/2)^n is not the same as 1/n²
yes it is?
How
oh wait
Maybe in a series it’s different rather than a function
no im pretty sure there the same function
in fact there are two different sequences
write out the first few terms of 1/2^n and 1/n^2
you should see quickly they don't match up
1/2 , 1/4
1/2 , 1/4
the first one 2 is at the base and n the exponent
and the second one : n is at the base and 2 at the exponent
the first one is way faster than the second
Am I washed or something 😭
write more terms
use Desmos
Look
the black curve reach 0 in a faster way thsn the blue one
because you compare
(1/2)^x and 1/2^x which are the same by the rule of exponents
But here we study 1/x^2 and 1/2^x
yep
if we go back to the original topic of this thread, you're on the right track about series convergence
im not sure if you've studied logic, but p => q does not necessarily mean q => p
?
your statement is backwards, so essentially if you have a convergent series with positive, decreasing terms, it does not necessarily imply that the sequence must be decreasing exponentially
Ya I see how that’s not equal
however if the sequence is decreasing exponentially (and the terms are positive), then the series is convergent
Oh okay
Ohh I see
okay let me reword it then
for a sum with positive decreasing terms the terms must decrease more than the last one to converge
Rightv
Right?*
yep
you got it 👍
to reword it to make it more concise it could be
"for a sequence with positive, decreasing terms, each term must be less than the previous one for its infinite sum to converge"
hopefully this helped
Well no not exactly
1/2 + 1/3 + 1/4 + 1/5 …
Is a sum that has terms being less that the previous one however it diverges to infinity
however it doesn’t decrease faster each time
yeah oops sorry, thats my fault
I am familiar with this
So the terms have to decrease more each time
yes
if you really want the concise definition of what it means for a series to converge in relation to its sequence
I thought this meant exponential but I guess not
the limit of the partial sums of a sequence must exist for its infinite series to converge
hm
limit as n approaches infinity ofc
if ur talking about a sequence that decreases exponentially strictly
right
that is a sequence in the form of ar^n
if |r| < 1, then the series converges
where a is the first term of the series and r is the common ratio
Didn’t someone say it doesn’t have to be expotienl?
Although I thought x^2 is expotienal
hm
okay okay
yeah so do you have a specific question you have orrrr
because there's a lot to talk about regarding series convergence that would probably be better suited for one of the channels
no im okay my original question was already awsnered
also how do you close this
oh there
x^2 isn't exponential?
this isn't an exponantial growth like e^x
because an exponential sequence is defined by the following rule : to get the next term you multiply by the same factor
x² is a polynomial growth.
which is slower
the factor to get the next term decereases each time
9/4 = 2,25 , 16/9 = 1,7777 , 25/16=1,5625 ...
.close