#Need help with reading a text from Stewart's Calculus
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tan(x)=sin(x)/cos(x)
Since if cos(x)=0 then sin(x)=1 (which happens when x=π/2+nπ) then youβre dividing 1 by 0 which gives a vertical asymptote
Therefore, all vertical asymptotes of tan(x) could be expressed as x=π/2+nπ where n is an integer
hope this helps
to be more precise, the limit at π/2+nπ does not exist because on one side it tends to positive infinity and on the other it tende to negative infinity
this is what creates the asymptote