#How do I show a series converges or diverges?
13 messages · Page 1 of 1 (latest)
CJ_:)
Sage says it's divergent, btw
e-(1+1/x)^x>1/x when x>3 and if we rerange terms we get e>1/x+(1+1/x)^x after that i got stuck 🍮
It is necessary for the general term to go to zero but it is not sufficient
What you can do is write
$(1+\frac{1}{n})^n
= exp(n ln(1+ \frac{1}{n}))$
Daddy_314
Then expand ln(1+x) when x = 1/n approaches 0
,close
.close