#Integrals (3)

134 messages · Page 1 of 1 (latest)

gentle epoch
#

I have an exercise to prepare for my exam on calculating integrals. I've tried several times to do it but I just can't do it. It's in French btw. Bounds x = -2 and 2 see attachment.

weak steppeBOT
gentle epoch
#

this is what I tried already but aint able to get the right answer (34/3)

#

Ion get where I am wrong tbf

#

<@&286206848099549185>

ivory aurora
#

,w x^2+2x-3=0

sudden vortexBOT
ivory aurora
#

,w integrate x^2+2x-3 from -2 to 1

sudden vortexBOT
ivory aurora
#

,w integrate x^2+2x-3 from 1 to 2

sudden vortexBOT
ivory aurora
#

this should be -9

#

and this should be 7/3

#

also an abuse of notation here, but I know that we're all a bit sloppy on the computer

#

@gentle epoch

gentle epoch
#

but this doesnt get me to 34/3 I think

#

Or either I'm wrong on the final resolution

#

bcs 34/3 is 11.33333

#

But I have -9 and 2.33333

ivory aurora
#

so the total area is just 9

#

$9+\frac{7}{3}=\frac{34}{3}$

gentle epoch
#

or since it's the air I get to -34/3 but i have to be pos. ?

sudden vortexBOT
#

Civil Service Pigeon

gentle epoch
#

you're right

#

thanks

#

You might have an idea for the 2nd one or you're busy ?

#

I can try something and send it here

ivory aurora
#

it seems like the same idea

#

so use the same logic you did

#

try to avoid computational slips this time tho

gentle epoch
#

yea sure

#

Ion know where I lost some stuff in my resolution tho, has to be a calculation error

#

,w integrate x^2+x from -1 to -1/2

gentle epoch
#

,w integrate x^2+x from -1/2 to 2

gentle epoch
#

I have this

#

for the 4 =>

ivory aurora
#

$\int^{2}{-1/2} (2x+1) \dd{x}=[x^2+x]^{2}{-1/2}$

sudden vortexBOT
#

Civil Service Pigeon

gentle epoch
#

I need to get the right f(x) nah?

ivory aurora
#

??

gentle epoch
#

I don't get it

#

what's wrong

ivory aurora
#

What is "the right f(x)" supposed to mean

gentle epoch
#

I need to get to x^2+x

#

right ?

#

So I intergrated it

#

Or either i didn't understood ur question

#

might be my fault my main language's french so im trying my best

ivory aurora
#

Tu as déjà intégré (2x+1) à (x^2+x)

#

(Le français n'est pas ma langue maternelle, mais j'ai essayé) 🤷‍♂️

gentle epoch
#

Sure no worries we can keep going in english tho i u prefer, but wym by am I integrating the antiderivative, like wheres the mistake

ivory aurora
#

there's no reason to integrate x^2 + x

#

it already came from integrating f

gentle epoch
#

so what should i do ?

#

this ? ,w integrate 2x + 1 from -1 to 2

#

,w integrate 2x+1 from -1 to 1/2

ivory aurora
gentle epoch
#

Oh sorry then

ivory aurora
#

np

gentle epoch
#

,w integrate 2x+1 from -1 to -1/2

gentle epoch
#

,w integrate 2x+1 from -1/2 to 2

gentle epoch
# sudden vortex

and on the first one, did I had to integrate as I did or it had to stay like this

ivory aurora
#

$\int^{1}{-2} (x^2+2x-3) \dd{x}=\left[\frac{1}{3} x^3+x^2-3x \right]^{1}{-2}$

sudden vortexBOT
#

Civil Service Pigeon

gentle epoch
#

so this was right fine, just a calculator mistake

ivory aurora
#

this is fine (barring the arithmetic mistakes)

#

this had the same issue I mentioned earlier

gentle epoch
#

alright thanks, if u got time i just got two more, one that looks like these and one for the volumes

ivory aurora
#

can you send a screenshot please

gentle epoch
#

yea sure

#

ion why they sent like that

#

so the last one

#

I need to find the air between the two functions

ivory aurora
gentle epoch
#

on this one ion really know how should i do, should i do f(x)-g(x) ?

#

and from 0 to 1

ivory aurora
#

,w graph y=x+x^2, y=3x

sudden vortexBOT
ivory aurora
#

but yeah, just integrate the difference

gentle epoch
#

you're right

#

like this ?

#

ig

ivory aurora
#

the line is above the curve so it should be $$\int^{2}{0} (3x) \dd{x}-\int^{2}{0} (x+x^2) \dd{x}$$

sudden vortexBOT
#

Civil Service Pigeon

ivory aurora
#

don't forget the dx either

gentle epoch
#

perfect

#

lm try it and I'll see if i don't do any calculating mistake

#

sounds good

#

this the last one that I got

ivory aurora
#

The idea is that when you rotate the curve, the solid you get has a bunch of circles as cross sections

#

I’ll let you look up a visual of that yourself

#

But the distance from the x axis to the curve is your radius

gentle epoch
#

I've done this already ion know if its right

gentle epoch
ivory aurora
gentle epoch
#

but since it starts at 1, shouldnt i start a 1 ?

#

and yea the dx thanks

ivory aurora
#

It’s a function of x, so you integrate over the values of x

#

Also, if that were the case, your upper bound would be wrong then

gentle epoch
#

so if I have somethinf like that at my exam I'll have to go from 0 to 2

ivory aurora
#

Sure

gentle epoch
#

ok

#

so

#

,w pi.integrate(x+1)^2 from 0 to 2

gentle epoch
#

its this ?

#

oh no

#

forgot the radical

#

,w pi.integrate(x^1/2+1)^2 from 0 to 2

gentle epoch
#

thanks a lot man

#

u might've saved me there

#

good evening

weak steppeBOT
#

If you are done with this channel, please mark your problem as solved by typing .close

gentle epoch
#

.close