#factorial
11 messages · Page 1 of 1 (latest)
?
k+1 copies of k! - 1 copy of k!
$(k+1) \times k! - k! = (k+1) \times k! - 1\times k! = [ (k+1) -1 ] \times k! = [ k ] \times k!$
Pfötchen
11 messages · Page 1 of 1 (latest)
Can somebody help me
Even with the solution i can’t understand
?
k+1 copies of k! - 1 copy of k!
$(k+1) \times k! - k! = (k+1) \times k! - 1\times k! = [ (k+1) -1 ] \times k! = [ k ] \times k!$
Pfötchen