Trigonometry is not my strong suit

[full elm]

I'm trying to do this seemingly simple task but I'm stuck, I have found 'to' but I cant get 'mo' or find a representation of w'

W is a variable not a force or anything

Any help would be so much appreciated, I know I'm missing something simple

[zealous elbow]

Hi

I didnt understand ur question

What are u trying to find

@full elm

[full elm]

W'

[zealous elbow]

What is h

And d

[zealous elbow]

What are those 2

[full elm]

There is no lone h ht and ho are separate parameters

d is the distance between them

[zealous elbow]

d is the blue arrow?

[full elm]

Yep

[zealous elbow]

How is OT = d^2 + (ht - ho)^2

Is that given?

Do u have any angle given?

[full elm]

The 90s at the bottom

[full elm]

I realize now i forgot to take the root of to²

[zealous elbow]

Do u have any coordinates?

Of any point

[full elm]

No, I'm not looking for a numerical value though

[zealous elbow]

Hmmm

[full elm]

Just a representation

[zealous elbow]

Can u send me the whole question

If u have it

[full elm]

I do not, but there is really nothing else to it

[zealous elbow]

Ok

Whats the last thing u took in trigonometry

[full elm]

Thing?

Like a course or a class?

[zealous elbow]

Idea

The last lesson u took

The last idea u took

[full elm]

I'm not sure what you mean

[zealous elbow]

Like what did u do last time in class

What did u take

[full elm]

Last thing I did was not really similar to this, it was just a generic find the area of rectangle inside a triangle

[zealous elbow]

Oh

So have u taken sin cos tan?

[full elm]

Yes

[zealous elbow]

What i dont understand is how are u supposed to find a numerical value if u dont have any number all u have is variables

Do u have any number given?

[full elm]

I'm not

I need to find a representation

[zealous elbow]

Oh

So like represent it as an expression?

[full elm]

Yes

[zealous elbow]

Ok

I think i know how

Is what ur trying to find tw?

tm*

[full elm]

Yes

[zealous elbow]

Ok

So

Sin(tOm)=TM/OT

[zealous elbow]

Do u understand this?

TM=Sin(tOm)xOT

[full elm]

Hooooo

[zealous elbow]

Do u understand how i got here?

[full elm]

Yep thank you

[zealous elbow]

Are u sure

U understood?

@full elm explain it to me so i can make sure u understood

[full elm]

Ok I'll try

Isn't this just tan though

[zealous elbow]

Do u know what soh cah toa is?

Memorize soh cah toa

It means

Sin= opposite/hypotenuse

Cos= adjacent/hypotenuse

Tan= opposite/adjacent

So sin of an angle is the side opposite to the angle divided by the hypotenuse

Memorize soh cah toa

Ok now i will explain

Basically

[full elm]

So can i find an expression for tOm this way?

Obviously explain first

I don't want to cut you off

[zealous elbow]

Its ok

U mean

tOm angle?

[full elm]

Yep

[zealous elbow]

Well yes u can find but i have a question before

Is OT and TB

Perpendicular

Or is it not given

[full elm]

Not given

[zealous elbow]

Oh

Ok

What u were saying is u cant use tOm in the representation for w?

[full elm]

Only if i find an expression

[zealous elbow]

Well this expression works

Unless u cant use angle tOm

Then we can replace it

[full elm]

With what?

[zealous elbow]

We can use tMo

[full elm]

True

[zealous elbow]

We can do Cos(tMo)=TM/OT

[full elm]

Cos right

[zealous elbow]

Yes

[full elm]

Yeah ok got it, thanks

[zealous elbow]

Then u can find the expression easier

Then TM=Cos(tMo) x OT

Cos(90) is 0

Hmm

[full elm]

That's interesting I guess

[zealous elbow]

Well there is another way

Did u take cosine’s rule?

Or Sines law works too

Did u take sine law?

[full elm]

Yeah both, cosine is the Pythagoras that works on any triangle and I know how to use sine but I have no description for it

But for both, we need more angles

[zealous elbow]

What are thoseangles

I see u named them

[full elm]

Alpha is the angle between x axis and tb, and the other one is 90 - a because there are 180 degrees in a triangle

[zealous elbow]

Hmm

Ok

So u have to use these angles in the expression?

I guess yes cuz u wouldn’t have named them

Well u can do the other small right triangle

Same as we did in the big one

But here do

Sin(a)= w’/w

Oh wait no thats the wrong angle

Wait i see something going on

[zealous elbow]

Look here

Does tm pass through midpoint of that segment?

[full elm]

It's not given

[zealous elbow]

U cant say u knew it graphically?

If this is the only given u have

[zealous elbow]

The only possible expression u can get is this

[full elm]

I think you're right and I'm missing something

Well, I'll try some more and update you

[zealous elbow]

I think they were supposed to give us that its passing through the midpoint cuz they named the angles for u and made it actually pass through the midpoint

And u said u did take cosine law