for the love of God what is the answer to this?!

[dim narwhal]

you could notice first that $(10^{-3})^0=1$ since $a^0=1$ for all real numbers except 0. Also the logarithm with base x, you can convert it to a base 10 logarithm with [\log_b(a)=\frac{\log_k(a)}{\log_k(b)}] for any base b and new base k.

[pseudo matrix]

fish

[civic gorge]

Also $log_{a}(x^{b})=blog_{a}(x)$

[pseudo matrix]

CJ_:)

[mint garden]

!nosols

[strange bridge]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[mint garden]

$\log_a(x^b)=b\log_a(x)$

[pseudo matrix]

SWR