#can you help mw with this question

24 messages · Page 1 of 1 (latest)

fluid ingot
austere ravenBOT
queen yew
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,,x' = \frac{\dd x}{\dd t}

heady frigateBOT
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lower quality boy (𝔸dωn𝓲²s)

fluid ingot
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I didn’t understand:(

queen yew
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Have you ever heard of the method separation of variables?

fluid ingot
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No

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😬

queen yew
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uff

fluid ingot
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😦

queen yew
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I will show

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You basically separate the variables

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one side x

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one side t

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and integrate both sides

queen yew
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,,\frac{\dd x}{\dd t} = (x+1)(\log t)e^{t+1+x} = (x+1)(\log t)e^te^1e^x

heady frigateBOT
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lower quality boy (𝔸dωn𝓲²s)

queen yew
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,,\iff \int \frac{1}{(x+1)e^x} : \dd x = \int e \log t \cdot e^t : \dd t

heady frigateBOT
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lower quality boy (𝔸dωn𝓲²s)

queen yew
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Now this looks nasty

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I give up

fluid ingot
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Yes ahaha but i understand i think