I’m stuck on question 11

[loud rock]

The diagonals of a rectangle are equal and bisect each other

Which means that AE = EC, and same for the other

@sacred cosmos

[sacred cosmos]

Here

What about DFC

[loud rock]

The triangle?

[sacred cosmos]

Ya

[loud rock]

AE = EC and BE = ED

SSS criterion

[sacred cosmos]

Isn’t ED apart of triangle DEC

[loud rock]

Yeah

[sacred cosmos]

And not apart of DFC?

[loud rock]

Oh, sorry I read the question wrong

Hold on

[loud rock]

But you can continue from here

The sides of rhombus are equal

So DE = EC = CF = DF

So AE = EC = CF and BE = ED = DF

[loud rock]

Once again SSS criterion

[sacred cosmos]

What about question B

[loud rock]

So since the two triangles are congruent, angles BAE = CDF

And since CF AND DF are equal, angle CDF = DCF = 58

So now that you have two angles, calculate the third angle (DFC)

EF is diagonal of rhombus, and the diagonals of rhombus bisect the angles,
Which means that DFE = FEC = 1/2 of DFC

[sacred cosmos]

Got it

[loud rock]

Yep

[sacred cosmos]

Thanks for ur help