#right triangle AOB

63 messages · Page 1 of 1 (latest)

uncut sailBOT Jun 1, 2024, 2:02 PM

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burnt oak Jun 1, 2024, 2:03 PM

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Hello guys

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I have this problem

errant forum Jun 1, 2024, 2:04 PM

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what do you need to find

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x and y?

burnt oak Jun 1, 2024, 2:05 PM

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The question was to define the length y as a function of x.

errant forum Jun 1, 2024, 2:05 PM

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you mean define length y in terms of x?

burnt oak Jun 1, 2024, 2:05 PM

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Most of my classmates use the Pythagorean theorem.

burnt oak Jun 1, 2024, 2:05 PM

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errant forum you mean define length y in terms of x?

Yes

errant forum Jun 1, 2024, 2:05 PM

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yea that is the way to go

burnt oak Jun 1, 2024, 2:05 PM

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y=f(x)

errant forum Jun 1, 2024, 2:05 PM

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x^2 + y^2 = 10^2

burnt oak Jun 1, 2024, 2:05 PM

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Yes

errant forum Jun 1, 2024, 2:05 PM

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y^2 = 10^2-x^2

burnt oak Jun 1, 2024, 2:05 PM

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I write something else

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And I'm not sure if this is right

errant forum Jun 1, 2024, 2:06 PM

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what is it

burnt oak Jun 1, 2024, 2:06 PM

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I defined its sides like this

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And after that said:

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-y^2=-(100-x^2)
y=root(100-x^2)

errant forum Jun 1, 2024, 2:07 PM

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was this your answer or the actual answer

burnt oak Jun 1, 2024, 2:08 PM

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That's how I define the all sides

errant forum Jun 1, 2024, 2:08 PM

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burnt oak -y^2=-(100-x^2) y=root(100-x^2)

looks good

burnt oak Jun 1, 2024, 2:08 PM

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Without using the Pythagorean theorem

errant forum Jun 1, 2024, 2:08 PM

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i just like to solve for y

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using pythagorean theorem

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so its like

burnt oak Jun 1, 2024, 2:09 PM

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does my answer stand mathematically?

errant forum Jun 1, 2024, 2:09 PM

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y^2 = 100-x^2

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y = √(100-x^2)

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so the function is just

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y(x) = √(100-x^2)

burnt oak Jun 1, 2024, 2:09 PM

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Yes

errant forum Jun 1, 2024, 2:09 PM

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great

burnt oak Jun 1, 2024, 2:09 PM

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This part

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Stand mathematically?

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AB OB OA are the sides.

errant forum Jun 1, 2024, 2:10 PM

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i mean

errant forum Jun 1, 2024, 2:10 PM

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burnt oak -y^2=-(100-x^2) y=root(100-x^2)

how did you get from 100+x^2+y^2 to here

burnt oak Jun 1, 2024, 2:11 PM

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The AB =10

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OB=y and OA=x

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errant forum Jun 1, 2024, 2:11 PM

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in my opinion i dont think it stands

burnt oak Jun 1, 2024, 2:11 PM

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So the only possible way is the Pythagorean?

errant forum Jun 1, 2024, 2:12 PM

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because there isnt really a way to go from 100+x^2+y^2

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and isolate y

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because you cant really manipulate the equation

errant forum Jun 1, 2024, 2:12 PM

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burnt oak So the only possible way is the Pythagorean?

best way yes

burnt oak Jun 1, 2024, 2:12 PM

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Ok

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Thank you!

errant forum Jun 1, 2024, 2:12 PM

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use it to be safe

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no problem

burnt oak Jun 1, 2024, 2:12 PM

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Almost 100/100 at exams

errant forum Jun 1, 2024, 2:12 PM

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🔥

burnt oak Jun 1, 2024, 2:12 PM

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-3 on this...

errant forum Jun 1, 2024, 2:12 PM

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:(

burnt oak Jun 1, 2024, 2:12 PM

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It's ok

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Happy for this!

errant forum Jun 1, 2024, 2:13 PM

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97/100 still excellent

burnt oak Jun 1, 2024, 2:13 PM

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👍

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How I can close this thread?