#Estimation lemma for contour integration
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The integral im trying to evaluating is the integral from negative infinity to positive infinity of cosx/x^2+1 in dx
Already did all the stuff, like defining the entire contour's value (Which if I'm not wrong is pi/e) and I just need to prove what I wrote in the title
Gamma usually refers to the parametrization of the contour
The contour integral of a holomorphic function is zero
If we apply the Cauchy integral theorem
But in this case, you must take a path that encloses a residue of the function
Which function did you use
i said i was integrating cosx/x^2+1
as there was just a pole in i (and another in -i, which i didnt take because i was considering only the upper bound. i had so the contour integral of cosz/z^2 in the contour c (which is all the semicircle, that give with the residue theorem pi/6) equal to the integral of my f(z) from -R to R and the integral of the curve i choose to call gamma
cosz/z^2+1
/(z^2+1)
yeah i know that
but i wasnt struggling with that
i was struggling with the estimation lemma
to prove that the integral of the curve (in my case gamma) of my f(z) was 0
It's not zero ... It's why we compute the residue of f at z = i
The estimation lemma is used to make a part of the integral "vanish" as R goes to infinity
@visual sail as Daddy_314 says. Here, you have to switch to exp(iz) otherwise your integral does not tend to 0.
Here is an exemple with your integral
hope it will help you
yeah,as i said in my paper i did that (i didnt said the part where i changed from trig to exp because it was obvious). im struggling only to prove with estiamtion lemma that the integral of the curve of the contour is 0
i did that on the photo
yeah i saw it