How is r³ + 3r² + 3r + 1 = (r + 1)³?

[sick stump]

How can I convert it to (r + 1)³? Is it also known as "factoring"?

[wooden thicket]

There's a formula for this

It's simply just the (a + b)^3 formula

[trail compass]

ye

[sick stump]

Oh, and I have heard it is called the "perfect cube" or something similar. If I have to guess, it is because the power (I forgot the right term) is going from three to zero.

[sick stump]

I see, thanks

[wooden thicket]

Yea to summarize u just need to multiply (a + b)(a + b)(a + b)

With a = r and b = 1

So (a + b)^3 = a^3 + 3a^2b + 3ab^2 + b^3

[sick stump]

Oh, also, what's the difference between factoring it normally (on my binomial, trinomial) and factoring this using the a b formula? (I have to try to factor this using the other method after eating, brb.)

[wooden thicket]

Factoring normally is like trying to look into any patterns in ur binomial/trinomial

Which makes u get the answer

Whilst the ab formula just helps u find the answer of a cubic polynomial

[sick stump]

answer? (I am a bit dyslexic)

[wooden thicket]

r^3 + 3r^2 + 3r + 1 equals (r + 1)^3 by expanding the cube of the binomial (r + 1).

[sick stump]

So, when I see a polynomial and want to factor it, should I first determine whether it is a perfect cube or not?

[wooden thicket]

Yep it should basically get u the answer more easily

[sick stump]

Thanks.

[wooden thicket]

Np

[sick stump]

.close