#Someone Could help me with this?
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Sure
THANK YOU
What do you have so far?
Can I see?
I see
The way I would approach it is using the information to solve the height of the smaller triangle to get more information for the bigger one
what do you mean?
I'll draw it up quickly
damn
you got it here @lusty jolt
q1
aight lets see
in essence straight away we can fine one angle
180-(90+35)
icl i dont have a calc so imma just explain
okay
then use sine rule
y/sin(90) = 4/sin(35)
y = 4/sin(35)
yk what side im talking bout
the hypotenous
wait wait wait wait hold on
photomath told me the same
sin 90
but
i dont understand where you get it from
ohhhh
so now fine the other angle this one
180-(20+55)
and then do sine rule lastly
x/sin(20) = 6.97/sin(105)
icl it sounds confusing cuz i havent labelled nothing
yeah
Dawgs you don't even need sine law, you can use SohCahToa twice and then subtract 4 from the answer ๐ญ
yeah fairs
thats true
๐คฃ
okay im just gonna copy that and fuck up my teacher
4/tan(35) = y
ahlie
then tan(55) = 4+x/y
ytan(55)-4
i didnt spot that icl
wait are u sure?
me?
@novel jungle
i got 4.2 to 2dp
Pretty sure ๐ญ
yeah should be fine icl idek how i didnt spot that
i might of miscalculated
im sure that next day he's gonna ask me about how i actually did this and im gonna answer no idea
not solving this even with ai
wai tlemme explain
look
yk how socahtoa works right
yes
alr
uhm
i didn't note that in my notebook
he didn't even teach me about those laws
just sohcahtoa
lemme write it down
That's all you need for this
the hell is that
its very late here, im going to bed
fuck this
thanks yall for the help
idk man, lots of exposure to different problems and repetition? ๐ญ
I'm not amazing so idk where to point you to for that ๐ญ
get to alevel and u will be up until 8am