This question is driving me up a wall

[thorn hill]

You guys are right. There's no answer

I'll take the 0

I can't do this shit

[small sand]

first u make the scale

like 10mph = 1 cm

so if the speed is 190mph then ur lenght of the line would be 19 cm

so make that line w bearing of 120°

it's a

see u draw the 19cm line and 1.5 cm line

then use the parallelogram law

the purple line which i have drawn is the resultant vector

measure the length of the purple line

and using the scale 10 mgh = 1 cm

u can find the speed

[thorn hill]

I got the speed for this

It's 197.92

[small sand]

so what u need?

[thorn hill]

I'm looking for the direction

Nothing I've tried works

[small sand]

which angle are u finding?

@thorn hill ?

[thorn hill]

tan^-1(164.54/110)

Idk if I'm supposed to add or subtract 90

[small sand]

from this image can u show which are u finding

[thorn hill]

I'll try

[small sand]

ok

[thorn hill]

I'm looking for the direction of the resultant

[small sand]

Ok

can u tell me what speed did u get?

[thorn hill]

197.92

[small sand]

I'm getting 3.8 degrees in anticloxkwise direction

Clockwise*

[thorn hill]

That's not correct

[small sand]

wait a min lemme recheck

@thorn hill

[thorn hill]

I already tried that too

It didn't work

[small sand]

Try 123. 76

@thorn hill

[thorn hill]

ok

One of them is right

How'd you get it?

[small sand]

yes

see they have asked the bearing right

[thorn hill]

yes

[small sand]

so we have to take in the angle from n to the resultant vector

[small sand]

So that angle w have to calculate

So I had used the sin rule to calculate the small angle which I got was 3.76

then i had added 120 to it

[thorn hill]

Ok

[thorn hill]

Thank You