trig help :(

[twilit ibex]

How did you get these?

[meager sage]

mathway...

[twilit ibex]

wow

not the math way to go

You can substitute x = cos(t)

Then you get

2x² - x - 1 = 0

... a quadratic equation

Then you calculate the solutions in terms of x and then resubstitute!

[meager sage]

i got x=1,-1/2

and by resubstituting you mean what exactly?

i was sick during this part of the unit haha

[twilit ibex]

✋🏻 😉

[twilit ibex]

correct

Now

resubstitution means

We subbed x = cos(t)

and we are interested to get the solution in terms of t

so we do

[keen rivet]

𝔸dωn𝓲²s

[twilit ibex]

Now you solve for t

First equation is quiet easy

At what t does cosine become 1 between 0 and 2pi

[meager sage]

2pi/3?

right? on the unitcircle?

wait no its 0

[twilit ibex]

yes

and there is one more

[meager sage]

pi?

but thats negative?

and if alpha is in quadrant 2 wouldnt the answer be sqrt(3)/1?

[twilit ibex]

2pi?

[meager sage]

ohhhh

right

[twilit ibex]

nwow

cos(t) = -0.5

[meager sage]

ok and how do i right that in terms of pi

[twilit ibex]

arccos of -0.5

[meager sage]

so pi/3?

[twilit ibex]

that would be for 0.5

[twilit ibex]

this for -0.5

[meager sage]

no pi/3

no 2pi/3

[twilit ibex]

huh

2pi/3 yes

and 4pi/3 to end this horror

[meager sage]

ok... thanks and im sorry

[twilit ibex]

why are you soory?

if you have questions out with them

it'S ok

[meager sage]

ok um i already put those 2 answers in and its saying its wrong so um...

[twilit ibex]

well maybe you dont put them in correctly

[twilit ibex]

without pi

it says

pi already there

0, 2/3, 4/3, 2

[meager sage]

ok thank you its correct !!!

[twilit ibex]

after so many hours hahaha

that's what i meant by horror