#Can someone help me with these 2 questions (trig ratios)
brittle iceBOT
hollow parcel
For number 2
Remember that csc = 1/cos
Wel if you know csc = 1/cos
Then you could say 1/cos = -2root3/3
Now solve for cos
Remember that cot csc and sec are all reciprocals of tan sin and sec
Wait wait
Mb
Csc is 1/sin
Not 1/cos
hollow parcel
Yes
woven scroll
and you just use the identity, cos^2+sin^2=1
you will get sine value from the given cosecant relation
woven scroll
and you just use the identity, cos^2+sin^2=1
and you plug in the sine value in this identity
so you will get the cos^2 value
you will then apply sqroot to find the value of cosine....
got it?
hmm
hollow parcel
It also says that tanx is less than 0
woven scroll
yes, that helps us to eliminate one of the cosine values we get by applying sqroot
bruh... you get two values for cosine
in which one of the cosine value contradicts the case where tanx<0. so you eliminate that value
and will result in one solid answert
got it?
why? what is stopping you?
where do you find the difficulty?
ok
start by finding the sine value from the given cosecant value
wait
dm me
hollow parcel
You don’t need to do all that
You can just write out a right triangle with an angle theta
Rewrite sin
Which is just the numerator and denominator of csc flipped
Which will give you -root3 /2
Now you know the hypotenuse of the triangle is 2
And the side opposite Theta is -root3
Given you know the Pythagorean theorem
You should be able to find out the 3rd side of the right triangle
Ultimately giving you the cos value
woven scroll
solved bro, thatnks for your help