#10 question rest of practice
134 messages · Page 1 of 1 (latest)
@hollow sundial I do need help these one s I understand you're tired too
Yeah, it’s kinda late where I am , but if no one answers these, I’ll definitely help tmr 👍
<@&286206848099549185>
10 question rest of practice
@opal wedge
<@&286206848099549185>
@plush stag may you help me with these questions
What q you need help with?
All of them I got the question question right on some but some of them I don't know how I got it
This my work
For which question
can u show better pic, not dark perhaps
This picture is my work I apologize it is unorganized
I'm not sure what I used for each question
I need help with 11-20
For 11
There is 21 numbers
0 counts ad a number
You thought that theres 20 numbers from 0-20
Doing 8/20, 2/5
When its actually just 8/21
12*
For 13:
Replace n with 3k and see if you can rearrange it to be in the for 3(x)
Where x is an expression in terms of k
Like plug in n with 3
3k
May you explain this one more
Because any integer multiplied by 3 is a multiple of 3
How many prime numbers are between 0-20
Where'd the 21 come from
Oh so you count all the prime numbers
Do you count 0 as prime number
So you see the pattern is a multiple of 3 like if the equation equal 3, 6, 9 etc
0 is not divisable by itself so not prime
Oh ok where is the 21 coming from I see 8 prime numbers wouldn't it be 8/20
Count from 0-4 on your habd
Hand
Hiw many fingers do you use
Let 3k be denote a multiple of 3
2(3k) + 3
6k + 3
3(2k+1)
Since 2k+1 is an integer, 3(2k+1) must be a multiple of 3
4
Oh ok so I would count (0-20)
Yes
Because it says “in the data set (0…20)
Which means thst it wants 0 to he counted as a number
If it said BETWEEN 0-20 i wouldnt
Oh ok got Cha and since out of the 2(3)+ 3=9 it makes it a multiple
Oh gotcha omgosh
Any other ones you need help with?
Thank for explaining it more
Thank you both for helping me
Aw thank you no one has ever complimented me before about that ❤️
@echo saddle @glacial garnet The last ones I need help with is 15-20 I should be ok after that. I understand if you both need a break too
For 15
Lets say you had x³+2x²+x
You always want to get to ax²+bx+c if possible
Because that allows you to do the diamond/x game
Or quadratic formula
So what could you factor out of x³+2x²+x
To get to ax²+bx+c
@jolly panther
X^3 and the x along with the 2x^2
Show me a factored out version
Since there all three GCF with the x
Yes
You would break down x(x^2+2+x)
Yay!
4? Multiples of 4
The x's
Yes
So could you say that 2x³+4x²+2x factored out is 2x(x²+2x+1)?
Would the 1 be 3x?
What do you mean?
I never mind I was adding multipling it would be 2x
Yep
That looks good
X(x-6+9)
No
There is no x in the 9
Do you know the diamond game
Otherwise known as x method
@jolly panther
It's (x-3)(x-3)
Yep
(x+6)(x+7)