#Help with this question pls
11 messages · Page 1 of 1 (latest)
that approach requires a to be constant
$v = \int a dt$ is the same thing as $a = \odv vt$, but the second one is more useful here
pnoןɔ
if you've learned the integrating factor method, that would be a good approach here
yh i know, but is there no way to do it using the integral?
the integral approach only works if a is not a function of v