#Help with this question pls

11 messages · Page 1 of 1 (latest)

dawn moonBOT
frigid gulch
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a = dv/dt

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adt = dv

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at + c = v , right?

balmy flare
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that approach requires a to be constant

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$v = \int a dt$ is the same thing as $a = \odv vt$, but the second one is more useful here

hard spruceBOT
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pnoןɔ

balmy flare
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if you've learned the integrating factor method, that would be a good approach here

hardy flare
balmy flare
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the integral approach only works if a is not a function of v