fringe ice
A point with coordinates (x,y) moves along the curve y = x+(2x+3)^1/2 in such a way that the rate of increase of x has the constant value 0.06 units per second. Find the rate of increase of y at the instant when x =3. State whether the y-coordinate is increasing or decreasing.
Why is it, that in the last step, we only take the positive value instead of taking both +ve and -ve 1/3?
pls help i have as maths exams soon 😭
jaunty patioBOT
viral abyss
A point with coordinates (x,y) moves along the curve y = x+(2x+3)^1/2 in such a ...
When you take the square root of a number you always take the positive value.
When you take the square root of a variable you will have two solutions
,w plot y = sqrt(x)
wheat kelpBOT
fringe ice
When you take the square root of a number you always take the positive value.
Wh...
OOOHH
viral abyss
Notice how taking the square root of a number
fringe ice
wait i think i'm understanding it almost
viral abyss
is only defined for y > 0 or y = 0
fringe ice
is only defined for y > 0 or y = 0
i don't get it
viral abyss
Look at the graph
viral abyss
aint no such thing that the square root of 1 is 1 or "-1"
it's here always the positive value
but the equation x² = 1 has two solutions, x = 1 or x = -1
that'S the difference
fringe ice
ok so when there is number only + value but when there is a variable there are +ve and -ve values?
viral abyss
yea
viral abyss
becauses when you take the square root of x²
you end up with |x|
and absolute value you would have two cases which result to 2 solutions
but this step is usually skipped
fringe ice
damn
wheat kelpBOT
𝔸dωn𝓲²s
viral abyss
but that's the explanation
