help me

[glass elbow]

i need to find sin cos tan

i finished sin a cos a and tan a but idk how to find sin b to tan b

[kindred arch]

sin B = b/c
cos B = a/c
tan B = b/a

[glass elbow]

do i just apply this to get sin b to tan b?

[kindred arch]

ye

[kindred arch]

what do you mean?

sin b to tan b?

[glass elbow]

sin b cos b and tan b i meant sorry

[kindred arch]

sin B = b/c
cos B = a/c
tan B = b/a