#How do I solve for V_B
272 messages · Page 1 of 1 (latest)
divide both sides by that ()
i did
i got 0.2433/0.203
Post marked as solved by @viral swan.
Use .unsolved if this was a mistake.
.unsolved jk but you should verify the RHS with a calculator before making sure its wrong
Post marked as unsolved by @viral swan.
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you shouldnt be getting a fraction
you should get a number instead
can you show how you simplified the RHS
j is not e^(j0)
theres a lot of things wrong here
just fix them one at a time when we come across them
@shell terrace quick question
yeah
,,e^{j\pi/2}
mtt
what do you think this simplifies to
no its j
but I had you stumble with that h
reminder that you cant rush this
also theres nothing stopping you from saying $$V_B=\frac{\displaystyle\frac{12e^{j0}}{62.83j}+\frac{12e^{j\pi/2}}{-79.6j}}{\displaystyle\frac{1}{62.83j}+\frac1{50}+\frac1{-79.6}j}$$ then entering the entire RHS into a calculator and getting $one$ number out
mtt
thats usually how you write it
I can confirm you get 12.000e^(-j2.073) when rounding the r and theta to three decimal places
my calculator cant do that
my calculator doesn't work with imaginary numbers
also i screwed it up
again
I think its better if you write it like this so that your problem is only in calculating one big number
my calculator doesnt know what imaginary numbers are
wdym
do you understand
yes
without j?
on paper?
no
on here
have this be your first line
oh okay
🤦♂️
you gotta notice
you only understood when I gave you a direct instruction
that means 0% of this is being understood
100% of it is me telling you "write this down as your first line"
what calculator are you using
fx-82ES PLUS
that sounds expensive
oh wait I recognize these
yeah thats mine
now you can see its very good at giving you exact answers as long as youre only working with real numbers
yes
so the next step is to combine like terms on the denominator
and simplify the numerator
no
which then simplifies to?
1200/6283
wheres the j
oh you just noticed
yes
now for th eother one
ok so
e^(jπ/2) = j, you got that correct earlier
yes
so then its just 12/-79.6
yep
thats not a valid move
o okay
we havent done the denominator yet
ok i swapped it
now for the denominator
i can combine the first and last fraction?
yea you gotta fix that
and what's 1/(1/j) then
j?
yea
ok i got j142.43
what
you can type 0.003353 j
alr
the denominator is now 0.02 + 0.003353 j
wait how did u get that
i took out 1/j
1/j = -j yes?
you took out a -1/j
wait
,,\frac1{-79.6j}=-\frac1j\frac1{79.6}=\frac1{79.6}j
mtt
ah
coolgamer123
thats correct
ah
,, -\frac{1}{j} \cdot -\frac{1}{62.83}
oh okay
s
so
,, \frac{1}{j} \cdot \frac{1}{62.83} + \frac1{-79.6j}=-\frac1j\frac1{79.6}=\frac1{79.6}j
coolgamer123
wait shoot
youll need to keep editing that
,, \frac{1}{j} \cdot \frac{1}{62.83} + \frac1{79.6}j
coolgamer123
1/j is?
-j
,, \frac{-j}{j} \cdot \frac{1}{62.83} + \frac{j}{79.6}j
,, \frac{-j}{62.83} + \frac{j}{79.6}j
no idea what youre doing
,, \frac{-j}{62.83} + \frac{j}{79.6}
coolgamer123
there?
what do i put in place of j
🤔
,,\qty(\frac1{79.6}-\frac1{62.83})j
mtt
coolgamer123
wait I think we accidentally swapped something
coolgamer123
wait no
sure
,, V_B=\frac{-\frac{30}{199}-\frac{1200}{6283}j}{0.003353 j+0.02}
coolgamer123
convert to polar form?
this is done so that in the third line, you have the convert to polar form formulas only use one number
also try this
write as a separate step what numbers you put in
so √((-30/199)^2 + (-1200/6283)^2) would be part of the third step
okay
what number you get out of will be part of the fourth step
oops i meant r_2 for the second part
and obv phi_1. and phi_2
your arctan formula only works for numbers with positive real parts
figure out how to get that fixed
you dont need to write it out like that, you could just
[V_B=\frac{\displaystyle\sqrt{\qty(-\frac{30}{199})^2+\qty(-\frac{1200}{6283})^2}e^{\qty(\pi+\arctan\frac{1200/6283}{30/199})i}}{\sqrt{0.02^2+(-0.003353)^2}e^{\arctan\qty(\frac{-0.003353}{0.02})i}}]
or that yeah
mtt
this is now your third step
the arctan(y/x) formula only works if x > 0
for x < 0 you do arctan(y/x) + π
also you get to add/subtract 2π to the angle at any time in case its not in the range you want
coolgamer123
,, \pi + 0.1661
coolgamer123
C:
coolgamer123
because like its in the tan quadrant of the unit circle
you just keep throwing things at the wall with no regard to how they fit in
go fix up the latex before you continue
not going to consider what gymnastics you did to think this is correct
.close