#what the frick (finding the turning point)

86 messages · Page 1 of 1 (latest)

pure loomBOT
lunar vale
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do you know why completing the square works

orchid breach
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well no

lunar vale
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do you know why (x + a)^2 = x^2 + 2ax + a^2 is true

orchid breach
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yes

lunar vale
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say you had x^2 + 2x + 2

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if you split this up into x^2 + 2x + 1 + 1,

lunar vale
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and so (x + 1)^2 = x^2 + 2x + 1

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so x^2 + 2x + 2 can be modified to look like (x + 1)^2 + 1

orchid breach
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yes so the turning point is -1,1

lunar vale
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now completing the square is using some patterns in when this happens to let you do this systematiclaly

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first off, lets notice the following

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x^2 + 2a x + a^2

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you know that if you have an x^2 + # x + # that fits this pattern, it can be written as a square, right

orchid breach
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yes

lunar vale
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now with something like x^2 + 6x + 5,

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we almost have the pattern

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we know from the "2ax" that the a in this case should be 3, right

orchid breach
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yes

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and 5 should be 9

lunar vale
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yep

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however we dont have a 9

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so we force one to appear

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you can + 9 - 9

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x^2 + 6x + 9 - 9 + 5

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you know that adding then subtracting the same number cant go wrong

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but now you can see you have the necessary 9 to make a square

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right

orchid breach
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right

lunar vale
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therefore (x + 3)^2 - 9 + 5

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or (x + 3)^2 - 4

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and youve turned x^2 + 6x + 5 into (x + 3)^2 - 4

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does completing the square make more sense

orchid breach
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yes but I wanted to know why that method works for finding the turning point

lunar vale
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do you know vertex form

orchid breach
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why is the turning point then -3,-4

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nope

lunar vale
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thats why

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do you know function transformations?

orchid breach
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probably not

lunar vale
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do you recognize f(x + 3) as "shifting 3 to the left"?

orchid breach
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no

lunar vale
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then that looks like stuff you can google and figure out on your own

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if youre so much in a hurry to rush finding out the why behind this

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Im afraid theres no other away around it

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however theres another way

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but you need to trust that a formula works for that one so it wont work out as good

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do you want to see it nontheless

orchid breach
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no ill google it

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thanks though, it’s probably too complicated

lunar vale
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its not

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you just dont know either of those things

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go on khan academy and go do function transformations and also vertex form of parabola

orchid breach
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but a formula isn’t an explanation for me

lunar vale
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:/

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you think khan academy only does formulas?

orchid breach
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if it’s just ‘oh you use this and thats why’ so WHY does THAT work

lunar vale
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have you even used khan academy before?

orchid breach
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yes rarely

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im not from america

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its not a big thing here

lunar vale
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I didnt know its american to use an online website like khan academy

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maybe you should try using it before giving it your critique

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you havent even seen how it teaches

orchid breach
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no it’s that nobody talks about it

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man how are you going to start an argument over this?

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never critiqued it

lunar vale
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you asserted that khan academy only teaches formulas

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(thats not correct)

orchid breach
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if that’s what you’re trying to do then i’m good i’ll ask google

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i was referring to you saying there’s a formula explanation

lunar vale
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maybe ping which statement youre referring to

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so that when I recommend you a website, you saying "but I dont want a formula explained to me" doesnt get misconstrued

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thats a misplaced modifier

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anyways,

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the "function transformations" will explain what happens with the +3 and the +4

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in (x + 3)^2 + 4, those serve more general purposes and dont need to be specific to parabolas

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they modify the location of where x^2 is graphed

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if you had 2(x + 3) + 4, the same thing applies, it modifies where 2x is

lunar vale
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this will confirm your suspicion that this moving-around idea is what's moving around the vertex of the parabola

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its form is a(x - h)^2 + k, where (h, k) is the vertex

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when you have both of these down, youll see why "completing the square" works to find the vertex of a parabola