#what the frick (finding the turning point)
86 messages · Page 1 of 1 (latest)
do you know why completing the square works
well no
do you know why (x + a)^2 = x^2 + 2ax + a^2 is true
yes
the x^2 + 2x + 1 looks like the right side of this
and so (x + 1)^2 = x^2 + 2x + 1
so x^2 + 2x + 2 can be modified to look like (x + 1)^2 + 1
yes so the turning point is -1,1
now completing the square is using some patterns in when this happens to let you do this systematiclaly
first off, lets notice the following
x^2 + 2a x + a^2
you know that if you have an x^2 + # x + # that fits this pattern, it can be written as a square, right
yes
now with something like x^2 + 6x + 5,
we almost have the pattern
we know from the "2ax" that the a in this case should be 3, right
yep
however we dont have a 9
so we force one to appear
you can + 9 - 9
x^2 + 6x + 9 - 9 + 5
you know that adding then subtracting the same number cant go wrong
but now you can see you have the necessary 9 to make a square
right
right
therefore (x + 3)^2 - 9 + 5
or (x + 3)^2 - 4
and youve turned x^2 + 6x + 5 into (x + 3)^2 - 4
does completing the square make more sense
yes but I wanted to know why that method works for finding the turning point
do you know vertex form
probably not
do you recognize f(x + 3) as "shifting 3 to the left"?
no
then that looks like stuff you can google and figure out on your own
if youre so much in a hurry to rush finding out the why behind this
Im afraid theres no other away around it
however theres another way
but you need to trust that a formula works for that one so it wont work out as good
do you want to see it nontheless
its not
you just dont know either of those things
go on khan academy and go do function transformations and also vertex form of parabola
but a formula isn’t an explanation for me
if it’s just ‘oh you use this and thats why’ so WHY does THAT work
have you even used khan academy before?
I didnt know its american to use an online website like khan academy
maybe you should try using it before giving it your critique
you havent even seen how it teaches
no it’s that nobody talks about it
man how are you going to start an argument over this?
never critiqued it
you started it here
you asserted that khan academy only teaches formulas
(thats not correct)
if that’s what you’re trying to do then i’m good i’ll ask google
i was referring to you saying there’s a formula explanation
Here
maybe ping which statement youre referring to
so that when I recommend you a website, you saying "but I dont want a formula explained to me" doesnt get misconstrued
thats a misplaced modifier
anyways,
the "function transformations" will explain what happens with the +3 and the +4
in (x + 3)^2 + 4, those serve more general purposes and dont need to be specific to parabolas
they modify the location of where x^2 is graphed
if you had 2(x + 3) + 4, the same thing applies, it modifies where 2x is
once you get that down, the next thing is vertex form
this will confirm your suspicion that this moving-around idea is what's moving around the vertex of the parabola
its form is a(x - h)^2 + k, where (h, k) is the vertex
when you have both of these down, youll see why "completing the square" works to find the vertex of a parabola