#Analysis- Area with integrals

70 messages · Page 1 of 1 (latest)

opal lynx Mar 26, 2024, 4:31 PM

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lime gustBOT Mar 26, 2024, 4:31 PM

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hybrid sandal Mar 26, 2024, 4:34 PM

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Let's forget the part below x axis

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Then let's forget the part on left of y axis

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Now

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Calculate the points of intersection of the two curves provided

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Mainly the x coordinate

opal lynx Mar 26, 2024, 4:35 PM

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Square 2

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Right?

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Ohhhh nvm, i see it

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With a system

hybrid sandal Mar 26, 2024, 4:35 PM

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opal lynx Right?

Idk
I don't really want to calculate it

hybrid sandal Mar 26, 2024, 4:35 PM

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opal lynx With a system

Huh?

hybrid sandal Mar 26, 2024, 4:35 PM

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opal lynx Ohhhh nvm, i see it

So u need no more help?

opal lynx Mar 26, 2024, 4:36 PM

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I need help

hybrid sandal Mar 26, 2024, 4:36 PM

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Ok

opal lynx Mar 26, 2024, 4:36 PM

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How do i find the intersection of the 2 curves?

hybrid sandal Mar 26, 2024, 4:36 PM

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Add the two given Eqn

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That will cancel out the y terms

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Calculate the value of x

opal lynx Mar 26, 2024, 4:37 PM

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Ohhh yeah

hybrid sandal Mar 26, 2024, 4:37 PM

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So now

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Let's define a part wise function

hybrid sandal Mar 26, 2024, 4:37 PM

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opal lynx Ohhh yeah

What is it?

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Tell me

opal lynx Mar 26, 2024, 4:38 PM

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+- sqrt 3

hybrid sandal Mar 26, 2024, 4:38 PM

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opal lynx +- sqrt 3

Are u comfortable with what has been suggested by @upper rover

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?

opal lynx Mar 26, 2024, 4:38 PM

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Not rlly

hybrid sandal Mar 26, 2024, 4:38 PM

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U wanna proceed further with my method or ask him for help?

opal lynx Mar 26, 2024, 4:39 PM

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Yes

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With ur method

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**

hybrid sandal Mar 26, 2024, 4:39 PM

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Okay

hybrid sandal Mar 26, 2024, 4:39 PM

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opal lynx +- sqrt 3

Define a function

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From root 2 to root 3

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It'll be following the eqn of hyperbola

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Then from root 3 to 2

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It'll follow the eqn of ellipse

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Okay?

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Now it's just simple integration

opal lynx Mar 26, 2024, 4:40 PM

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How do you define that function?

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Like i got that its from sqroot 2 to sqroot 3

hybrid sandal Mar 26, 2024, 4:41 PM

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You know function
U know the limits

hybrid sandal Mar 26, 2024, 4:41 PM

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opal lynx Like i got that its from sqroot 2 to sqroot 3

[(x^2 -2)÷4]^1/2 =f(x)

opal lynx Mar 26, 2024, 4:41 PM

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Okkkk

hybrid sandal Mar 26, 2024, 4:41 PM

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From root 2 to root 3

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Integrate it

opal lynx Mar 26, 2024, 4:42 PM

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Ohhhh and i get half of S2

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Right?

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Half of S2 or Half of S1

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The little area

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Nvm, i get it

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Ill proceed the same with the ecllipse

hybrid sandal Mar 26, 2024, 4:44 PM

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Ig the funcn I mentioned earlier was wrong

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I've changed it

opal lynx Mar 26, 2024, 4:44 PM

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Ok, i think i understant now, tysm !!!

hybrid sandal Mar 26, 2024, 4:44 PM

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opal lynx Ohhhh and i get half of S2

Half of half of s2

opal lynx Mar 26, 2024, 4:44 PM

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Ill go ahead and solve it

opal lynx Mar 26, 2024, 4:44 PM

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hybrid sandal Half of half of s2

Yes

hybrid sandal Mar 26, 2024, 4:44 PM

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opal lynx Ill go ahead and solve it

Good luck my lady

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Make sure to multiply final answer with 4

opal lynx Mar 26, 2024, 4:45 PM

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Ok

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Tysm, you are a genius fr

hybrid sandal Mar 26, 2024, 4:55 PM

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Can u please close the thread @opal lynx

opal lynx Mar 26, 2024, 6:28 PM

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i cant tho

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or i dont know how to

hybrid sandal Mar 27, 2024, 4:35 PM

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.close

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,close

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,close