Difference between f'(x) and [f(x)]' | Mathematics | Page 1

serene rainBOT Mar 24, 2024, 4:35 PM

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clever rune Mar 24, 2024, 4:35 PM

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and can you explain the logic between what the difference is between those two and what exactly they intend to show

red tinsel Mar 24, 2024, 4:37 PM

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The first one is basically only f differentiated (without chain rule yet), the 2nd refers to the whole thing including chain rule

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Basically:

[f(2x+4)]' = f'(2x+4) • (2x+4)'

clever rune Mar 24, 2024, 5:27 PM

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and f'(2x+4) is (2x+4)^2 + 5(2x+4) right?

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which would be like

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4(2x+4) + 10

red tinsel Mar 24, 2024, 5:28 PM

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no that's f(2x+4)

clever rune Mar 24, 2024, 5:28 PM

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right i meant like

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when we do f'(2x+4) the end result is 4(2x+4)+10?

red tinsel Mar 24, 2024, 5:29 PM

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how?

clever rune Mar 24, 2024, 5:29 PM

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what is f'(2x+4) equal to?

red tinsel Mar 24, 2024, 5:29 PM

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f'(2x+4) = 2(2x+4)(2x+4)' + 5(2x+4)'

clever rune Mar 24, 2024, 5:30 PM

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o yea thats just this with respect to x, that was what i meant

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aight ty

fossil salmon Mar 24, 2024, 5:55 PM

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.solved

#Difference between f'(x) and [f(x)]'