differential equation

[old tangle]

Can't solve this differential equation

[bitter patrol]

So you got basically:

y = ln|x²-1| + C

[old tangle]

Yes

[bitter patrol]

What is the problem exactly?

[old tangle]

And the correct answer should be ln(x+1) + ln(x-1)

[bitter patrol]

It's the same

[old tangle]

How do i get there?

From my answer

[bitter patrol]

ln(x²-1) = ln[(x+1)(x-1)] = ln(x+1) + ln(x-1)

It's a log rule.

[old tangle]

Oh

[bitter patrol]

log(ab) = log(a) + log(b)

[old tangle]

Thank you 👍🏻

[solemn hill]

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[old tangle]

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