#Please help...
51 messages · Page 1 of 1 (latest)
Hello, what do you think would happen if there was only 2 digits of numerics and letters while numerics were first and letters were second?
i dont fully get u
humor me for a sec
i want you to tell me how many possible ways a 2 digit code can go if the first digit is numeric and second is a letter
i guess u dont want help :/
hey sorry was eating
wont it be 240?
what is the multiplication to arrive at this number?
there are 10 numeric digits which are 0,1,2,3,4,5,6,7,8,9
and there are 27 letters in english alphabet
yep so 260 possible combinations
exactly
oh lol
what is that equation xD
wait no that would be incorrect
it would be 10x10x10x26x26
wouldnt that be incorrect
if its for this order it is correct
as altho the digits can repeat the letters have to be different so wouldnt it be 26 x 25
but we need to have all possible combinations of digits
given only 3 numeric and 2 letters exists
so now we need to find the amount of positions possibl
no because letters can be used more than 1 time
its not decreasing
oh yea it says different
ur right
i missed that
so its 10x10x10x26x25 right?
exactly
thank you so much
wait but here it doesnt specify the position
so it could ABC12 A1B2C AB12C ....
yes now we come to that
the positioning
this is where the combinations come in
btw the question is not about probability but combinatronix
forget this i found a better one
you gotta multiply this with 5 combination 3 or 5 combination 2
reasoning: since we need to select the possible places for letters (for example) after we choose 2 positions out of 5 the rest (which is 3) will be automatically numeric
so we only need the possible positionings of numerics or letters