#Can anyone answer this
104 messages · Page 1 of 1 (latest)
g(x) is the first derivative of f(x)
so for a maximum g(x) = 0 aka roots
and g'(x) has a change of sign before and after root from + to -
sofor what value f(x) is max??
Think
Oh I also just realized they are showing f(x) in the figure not g(x) so it's even easier
is that d
explain yourself
umm
its graph of g(t)
It's weird though
I have a feeling they made a typo
It would make more sense if the graph was g(t)
maybe
But assuming it's f(x) what would be here the max it's obvious
and if it is graph of g(t) d is max
b would be
d
wrong
still b??
the second condition is change of sign
- -> - for maximum
At which root does that happen
Where is g(t) > 0 and then g(t) < 0
Where does that happen
You got 3 roots
d is wrong
You cant say how the function proceeds further
@amber barn
i am confused @upper current
before a maximum the first derivative is positive and after it's negative
,w plot -x^2
Here example
max is at x = 0
tangent line slope 0
before that
the slope was positive and after it is negative
so between the root of the first derivative there was a change of sign from + to -
here look for which root the same happens
g(t) describes the slope of f(x)
at which root is g(t) > 0 before and after g(t) < 0
You only got 3 options
3 roots
d is wrong
what about a?
lemme think
ok
ok i understood that
continue then what should be the answer
a
looks like you didnt understand
how can you tell how g(t) behaves before a
you cant
so c is remaining really
now tell me
before c if g(t) is postive or negative and the same after c
omg i understood now , as the curve from c to d is below x-axis
g(t) is negative , and before c g(t) is positive , am I getting that right @upper current
Okay so our final answer is c if the graph if of g(t)
Here cosine is the first derivative of sine
And you see the exact same phenomenon
root at x = π/2 and change of sign from + to -
hence maximum
yes
For a minimum it's the opposite
You look for - to + change of sign
,w plot -sinx and -cosx between 0 and pi
now minimum and the yellow function the cosine goes from - to +
here function is minimum at pi/2
Yes
i got that
Thats literally it
necessary condition is always first derivative equal 0
If there are solutions
look for change of sign as that is the sufficient condition
- to - is max
- to + is min
thanks for understanding @amber barn
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