#Determining limits
stoic spokeBOT
midnight stirrup
limit as n approaches infinity?
crude night
i think it converges
final plover
limit as n approaches infinity?
yes
or actually not specficied
but I took it as infintiy
crude night
im fairly sure as it approaches inf it converges to 0
final plover
right to 0?
final plover
im fairly sure as it approaches inf it converges to 0
Yeah that's what im getting too
midnight stirrup
basically you have something like ~ n^(1/4) ... / n^(1/2) ... = 1 .../n^(1/4)... = 0
crude night
lemme plug it into wolfram alpha cuz u said online calculators say its divergent
final plover
basically you have something like ~ n^(1/4) ... / n^(1/2) ... = 1 .../n^(1/4)......
true makes sense
crude night
lemme plug it into wolfram alpha cuz u said online calculators say its divergent
says 0
final plover
i dont know how to use wolfram that well so I didn't try that
crude night
midnight stirrup
https://www.wolframalpha.com/input?i2d=true&i=Limit%5BDivide%5B%5C%2840%29%5C%28...
,w Limit[((x^1/4)+1)/sqrt(9x+3),x->inf]
final plover
Lol thanks!!
solar harborBOT
crude night
,w Limit[((x^1/4)+1)/sqrt(9x+3),x->inf]
id do this if i knew how to
or had the willpower to type out that many brackets
midnight stirrup
id do this if i knew how to
i copied this from your site
if you go to natural language it automatically provided the code
then do ,w [code]
midnight stirrup
shee the cheese you u need
crude night
we're different
midnight stirrup
literally
crude night
me when pickles in my burger 
final plover
literally
I had another question, when asked to find something like the fourth partial sum of sigma from n= 1 to infinity of 1/n^2, would it be 1/1^2 + 1/2^2 + 1/3^2 + 1/4^2 ?
midnight stirrup
i think yes
final plover
got it. Appeciate you!
crude night
I had another question, when asked to find something like the fourth partial sum...
ah basel
problem
midnight stirrup
.solved