Help solving | Mathematics | Page 1

waxen cosmos Mar 17, 2024, 9:54 PM

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keen wagonBOT Mar 17, 2024, 9:54 PM

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fading cloud Mar 17, 2024, 9:55 PM

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waxen cosmos

!status

keen wagonBOT Mar 17, 2024, 9:55 PM

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waxen cosmos

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

waxen cosmos Mar 17, 2024, 9:55 PM

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3

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I need to find the if

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I've got the right answer but I need to find the if

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@fading cloud

fading cloud Mar 17, 2024, 9:56 PM

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in example section?

waxen cosmos Mar 17, 2024, 9:56 PM

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no the if condition

fading cloud Mar 17, 2024, 9:56 PM

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i think they pretty much asking you for condition you found

waxen cosmos Mar 17, 2024, 9:56 PM

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fading cloud i think they pretty much asking you for condition you found

yep

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i need help solvin git

fading cloud Mar 17, 2024, 9:57 PM

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ok then tell me how did you come out with -3 and 7 from

waxen cosmos Mar 17, 2024, 9:57 PM

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-3 and 7?

fading cloud Mar 17, 2024, 9:58 PM

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yea like i wanna understand why you started this first

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how come you know?

waxen cosmos Mar 17, 2024, 9:58 PM

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WDYM

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i dont understand what ur saying

fading cloud Mar 17, 2024, 9:58 PM

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;-;

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let me repeat again

waxen cosmos Mar 17, 2024, 9:58 PM

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okay

fading cloud Mar 17, 2024, 9:59 PM

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you've wrote in example section and i wanna understand why you came out with these numbers

waxen cosmos Mar 17, 2024, 9:59 PM

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oh okay

fading cloud Mar 17, 2024, 9:59 PM

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should be to look at denominator?

waxen cosmos Mar 17, 2024, 9:59 PM

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yea so we're supposed to simplify those terms

fading cloud Mar 17, 2024, 9:59 PM

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oh

waxen cosmos Mar 17, 2024, 9:59 PM

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yea we need to look at the denominator

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from the beginning and end

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and find the domains

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and the ones that are not repeating

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is the if anaswer

fading cloud Mar 17, 2024, 10:00 PM

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is this the only problem or theres more missing information?

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because i see we have two unkown variables there

waxen cosmos Mar 17, 2024, 10:00 PM

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fading cloud is this the only problem or theres more missing information?

this is the only provlem

fading cloud Mar 17, 2024, 10:00 PM

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unknown*

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ok

waxen cosmos Mar 17, 2024, 10:00 PM

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we dont need to solve for the variables

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we just simplify as much as we can

fading cloud Mar 17, 2024, 10:01 PM

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you sure you got the answer right first? because you seem didn't

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ill check real quick

waxen cosmos Mar 17, 2024, 10:01 PM

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no the answer is correct

fading cloud Mar 17, 2024, 10:01 PM

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ah ok

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then you should write whats given on denominator you got and thats it

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e.g c=d/2

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instead of x

waxen cosmos Mar 17, 2024, 10:04 PM

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can u help me solve this actually

fading cloud Mar 17, 2024, 10:08 PM

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apply the exponet rule

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,, a^{b+c}=a^b \cdot a^c

waxen cosmos Mar 17, 2024, 10:08 PM

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okay

subtle agateBOT Mar 17, 2024, 10:08 PM

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アキラ (>_<)

waxen cosmos Mar 17, 2024, 10:09 PM

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okay i got 4

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how do we do sqrt of 2 ^ log 2 3

fading cloud Mar 17, 2024, 10:09 PM

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you dont need to

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it just stays the same

waxen cosmos Mar 17, 2024, 10:10 PM

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we're gonna have to solve that right?

fading cloud Mar 17, 2024, 10:10 PM

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no

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it's already solved

waxen cosmos Mar 17, 2024, 10:10 PM

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it says its wrong

fading cloud Mar 17, 2024, 10:10 PM

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ded

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,w \left(\sqrt{2}\right)^{4+\log _2\sqrt{3}:}

subtle agateBOT Mar 17, 2024, 10:10 PM

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Wolfram Alpha doesn't understand your query!
Perhaps try rephrasing your question?
Click here to refine your query online

fading cloud Mar 17, 2024, 10:10 PM

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oh man

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what did you put for your answer

waxen cosmos Mar 17, 2024, 10:11 PM

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4+ sqrt of 2 ^ log 2 3

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2 sqrt of 3

manic timber Mar 17, 2024, 10:11 PM

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waxen cosmos how do we do sqrt of 2 ^ log 2 3

since the log is base 2 u can cancel it

waxen cosmos Mar 17, 2024, 10:11 PM

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manic timber since the log is base 2 u can cancel it

okay do we get 3?

manic timber Mar 17, 2024, 10:11 PM

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yea

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thats what i got

waxen cosmos Mar 17, 2024, 10:12 PM

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so is the final snwer 7?

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it says its wrong

manic timber Mar 17, 2024, 10:12 PM

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i got 3 as the final

waxen cosmos Mar 17, 2024, 10:12 PM

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i tried 3 as final too its wrong

manic timber Mar 17, 2024, 10:13 PM

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sqrt(2)^4 * 2^(1/2)log(sqrt(3))

waxen cosmos Mar 17, 2024, 10:13 PM

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yep

manic timber Mar 17, 2024, 10:13 PM

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4* 2^1/4log3

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4*2^log(3^1/4)

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cancel the log

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wait

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im confused lmao

waxen cosmos Mar 17, 2024, 10:16 PM

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it says its wrong

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can u try finding the if for this problem

manic timber Mar 17, 2024, 10:16 PM

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ohh wait

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ic

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its 4* fourthroot(3)

waxen cosmos Mar 17, 2024, 10:18 PM

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oh yea thanks

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can u try solving this one

manic timber Mar 17, 2024, 10:19 PM

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manic timber its 4* fourthroot(3)

the problem was i forgot to put the 1/4 into the log before canceling

manic timber Mar 17, 2024, 10:20 PM

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waxen cosmos can u try solving this one

yea I can try

waxen cosmos Mar 17, 2024, 10:20 PM

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thanks

manic timber Mar 17, 2024, 10:21 PM

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ok so basically just factor top using difference of cubes and bottom with difference of sqaures twice

waxen cosmos Mar 17, 2024, 10:21 PM

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ye i need to find the domain

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i alr solved it

manic timber Mar 17, 2024, 10:22 PM

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waxen cosmos can u try finding the if for this problem

domain? but its in terms of 2 variables

waxen cosmos Mar 17, 2024, 10:22 PM

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basically

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we find the domain of the original expression

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and find the domain of the end result

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can u find those

manic timber Mar 17, 2024, 10:23 PM

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2c can't = d

waxen cosmos Mar 17, 2024, 10:23 PM

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okay

manic timber Mar 17, 2024, 10:23 PM

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cus of the hole

waxen cosmos Mar 17, 2024, 10:23 PM

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yep

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what else

manic timber Mar 17, 2024, 10:24 PM

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denominater cant be 0 so

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2c > -d

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and 4c^2 + d^2 is always positive unless both of them are 0

waxen cosmos Mar 17, 2024, 10:26 PM

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yea i got it

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thanks for helping

manic timber Mar 17, 2024, 10:26 PM

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np

solemn onyx Mar 18, 2024, 12:06 AM

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.solved

#Help solving