Solve

[dull oak]

convert e^0.16 to ln?

ln x = 16/100

100 ln x = 16

ln x^100 = 16

[frail smelt]

Can u show in paper

[dull oak]

I m out rn

I was just checking for any problems I could do lol

[frail smelt]

okoko

[dull oak]

but usually they tell ppl to do it with calc lol

[serene glacier]

Exact value in decimal or approximations is fine

[frail smelt]

ok how to proceed next

[pearl pivot]

maybe Newtons method of approximation

[serene glacier]

Or Taylor series

[pearl pivot]

Start with an initial guess of 1 as e^0 .16 is approximately 1

[frail smelt]

then

[pearl pivot]

I need to look up the formula I casnt be bothered sorry bro I goota watch TV

[dull oak]

or mclaurin series lol

[junior peak]

how many digits do you need

[frail smelt]

2

[junior peak]

do you know what a taylor series is

[dull oak]

e^x = 1 + x + x^2/2!

maclaurin series

[frail smelt]

this is confusing mern

[gray vortex]

approcimate it

[gray vortex]

maclaurin series for e^x

[dull oak]

it's just 1 + 0.16 + (0.16^2)/2

@frail smelt

for reference

2! is just 1*2

[frail smelt]

ok thank u i think i got it

[junior peak]

.solved

[devout sigil]

Solved

Post marked as solved by @junior peak.

Use .unsolved if this was a mistake.

[pearl pivot]

If you use.the Taylor or Mclaurin series wouldn't you have to show the amount of variation so you know its within two decimal places.

[junior peak]

doesnt look like this guy cares about that

[pearl pivot]

lol

that part allways triggered me

[serene glacier]

Mac lauda

[frail smelt]

.unsolved

[devout sigil]

Unsolved

Post marked as unsolved by @frail smelt.

Use .solved to mark as solved.

[junior peak]

oh good youre back

[gray vortex]

lauda lassun

[serene glacier]

Yes

[gray vortex]

wassup bro

[frail smelt]

bro can some one explain in a basic manner

i am studying highschool not cllg

[junior peak]

took you long enough to realize that doing 1 + 0.16 + 0.16²/2 is absolute bonkers

[frail smelt]

can u write in paper bro

[serene glacier]

If u don't understand Taylor series use linear approximation using derivatives and equation of tangent lines

[junior peak]

theres no paper work for this

the way theyre showing

its only that calculation

[gray vortex]

ay dude

whats so bonkers there

[serene glacier]

Gives bad approximation but might work

[frail smelt]

i only know taylor shift what the hell is taylor series

[gray vortex]

0.16^2=0.256

[serene glacier]

It's an art

[junior peak]

this is a class of Bonkers that is unfortunately above their current level

[serene glacier]

It's a way to approximate things

One of the most useful tool

They taught u equation of tangent lines using derivatives right @frail smelt ?

[pearl pivot]

Use Newtons Method of approximation and check with calculator

[frail smelt]

we are not allowed to use calculators in india

[pearl pivot]

What about to check the awnser?

[frail smelt]

no

[pearl pivot]

You dont have to show it in the working out

[frail smelt]

ok wats the conclusion ??

[serene glacier]

Use big number

[serene glacier]

At least ur taught this ?

[frail smelt]

no

[serene glacier]

Tf

[frail smelt]

yooo wat all u talking about

[serene glacier]

They asked u to show ur method ?

[frail smelt]

no iwas a step in a q

it*

ok all...wil confirm with others thank u all

.solved

[devout sigil]

Solved

Post marked as solved by @frail smelt.

Use .unsolved if this was a mistake.

[frail smelt]

[serene glacier]

This is the most simple one

[frail smelt]

thank you

bye

sis

[serene glacier]

Bye