#confused about how to get the fourth function
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i got the answer but i have no idea where the first -1 comes from
it is -1(-1)^n(n!)/(x^(n+1))
i thought it wouldve just been (-1)^n(n!)/(x^(n+1))
?
(-1)^n*n!/x^n
ah, this is just taylor series
the first -1 comes in when you plug in 1.
-1(-1)^1 = 1
which is what you get as f'(x)
My answer is right?
f(x) = negative 1/x is where the initial - comes from
had f(x) been 1/x instead, (-1)^n(n!)/(x^(n+1)) wouldve been correct