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[sturdy condor]

You made a mistake

f(x) = x^2 - x - lnx
f’(x) = 2x - 1 - 1/x

why did you write ln(1/x)

Now you can finish it

[sturdy condor]

Everyone makes mistakes

[sturdy condor]

I dont know how to solve for x

of course

so youre setting the derivative equal to 0?

2x - 1 - 1/x = 0

2x - 1/x = 1

multiply both sides by x to remove the fraction

2x^2 - 1 = 1

2x^2 = 2

can you continue it?

[coral glacier]

that is wrong

you forgot to multiply the right side

f'(x) = 2x - 1 - 1/x

set it equal to zero

2x-1-1/x = 0

multiply both sides by x

2x^2 - x - 1

then factor that and you have your 0s

just remember the domain of ln means you can only use positive x so f of negative x is undefined

[sturdy condor]

Right

Easy peasy

I got it wrong

I got x=1

Im supposed to find the intervals of increasing decreasing

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,rotate

[sturdy condor]

.solved