#Absolute value equation

7 messages · Page 1 of 1 (latest)

tight goblet
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| x^2+1| =2x.
Solution is 1

I got -1 and 1. Is it ok or maybe did someone just find 1? Thanks!

sonic kestrelBOT
topaz idol
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Since x²+1 > 0 for all x you can leave out the absolute value

tight goblet
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ok so it's just 1

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thanks

topaz idol
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.solved