#Help

47 messages · Page 1 of 1 (latest)

shy drum
spice karmaBOT
shy drum
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I found the first and second derivate

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I’m not sure how to solve for X when setting equal to 0

modern loom
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What did you get?

frigid sleet
# shy drum

show the work you currently have so far
its better if you type in the answers you believe is true into the boxes before screenshotting

if you want more general help that doesnt address what youre stuck on, theres a video on doing this: https://youtu.be/15awMHeP1Yc

fyi you can use Win + Shift + W or Cmd + Ctrl + Shift + 4 to screenshot the screen instead of taking a picture on your phone
the command save the part of the screen you want into your clipboard, then you can Ctrl + V that here
its fast and more "proper" that way

This calculus video tutorial shows you how to find the intervals where the function is increasing and decreasing, the critical points or critical numbers, relative extrema such as local minimum and local maximum values using the first derivative test, concavity, and inflection points using the second derivative.

Introduction to Limits: ...

▶ Play video
shy drum
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I dont have discord on my laptop

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But i know i have to set the first derivative equal to 0

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The problem im having is solving for x

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I have the first and second derivate

frigid sleet
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@shy drum

shy drum
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Well no id have to set the first derivative equal to 0

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To find increasing or decreasing

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And i cant remember how to solve for X for exponentials

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And i know they have to be positive so im not sure how that changes things

frigid sleet
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whats your first derivative then

shy drum
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2e^2x+e^-x

frigid sleet
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thast not correct

shy drum
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How so

frigid sleet
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you can use chain rule on e^(2x)

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the outside is e^x

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the inside is 2x

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so e^(2x) * 2

shy drum
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Oh 2e

frigid sleet
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so the derivative of e^(2x) is 2 e^x

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dont say 2e

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thats a misnomer

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say 2 e instead

shy drum
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I looked at the wrong problem

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But yeah

frigid sleet
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also use the chain rule on e^(-x)

shy drum
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-e^x

frigid sleet
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-e^(-x)

shy drum
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Right

frigid sleet
shy drum
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Mybad i glanced at it im ar work right now

frigid sleet
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"no" you say?

shy drum
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But still the problem im having is solving for X

frigid sleet
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you should put some more weight on your Nos next time

frigid sleet
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the bottom line has one x

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then you can "isolate for x" since there is only one x in the equation

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that means you just do operations to repeatedly move stuff from the LHS to the RHS

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moving e^ to the RHS is done by ln() both sides

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use these hints to work out the value of x

shy drum
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I see

shy drum
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.solved