#simple differentiation
23 messages · Page 1 of 1 (latest)
all i can think about is to multiply both sides of the equation by $$rt sin4x/cos^2x$$
Samii
but im not sure if its mathematically correct although it gets me an answer, ive seen an example which states that doing that is incorrect
oh look its the same question from last time
if you remember from earlier, this is the derivative we got
keep in mind latex doesnt know how to read math
if you want a sqrt to appear, you have to type \sqrt{ inside }
if you want a fraction to appear, you have to type \frac{ numerator }{ denominator }
you multiply both sides by √(sin 4x) / (cos 4x)
with that, youll get an equation that looks exactly like tan 4x + #x = 0
whatever that # is will be k
.solved