#integral

55 messages · Page 1 of 1 (latest)

jagged grotto
#

Whats the thing from this thing

queen pathBOT
jagged grotto
#

Like I mean the f(t)

#

I don't know how to put it

jagged gazelle
#

integration?

#

integrate the function and add a constant since it is indefinite

jagged grotto
#

What

#

Don't leave now sami

#

I don't want to add constants

kindred swift
#

Are you asking if your integral is correct for f'(t)

kindred swift
jagged grotto
#

I thought this was just a funny thing I can do

#

I want f(t)

#

I already tried on the right

#

The fraction is confusing me

kindred swift
#

Also please tell me what you've written for f because I can't tell what it is

jagged grotto
#

Yeah I wanna know the f(t) to f

kindred swift
#

NVM I misinterpreted 6ou

jagged grotto
#

-0.5/2 *t^-1 1/2

jagged grotto
kindred swift
#

And it's not divided by 2 it's, divided by 1/2

jagged grotto
#

Yea but I thought because the 2 is the bottom thing

#

I thought it'll be 0.5*1/2

#

Idk man

kindred swift
jagged grotto
#

That's what I did though

kindred swift
jagged grotto
#

It's the exponent

#

Or whatever you call it

#

Sorry I'm a German student it's complicated

#

We have different terms probably

kindred swift
#

But you've raised t^-1

#

( in your answer )

jagged grotto
#

It was t^-1/2

#

And I made it t^-1 1/2

kindred swift
#

What's -1/2+1 ?

jagged grotto
#

Ohhh

#

So just 1/2

kindred swift
#

Yep

jagged grotto
#

Got it

kindred swift
#

And, when you're dividing 0.5 by 1/2 it is the same as multiplying by 2

#

0.5x2=1 so your answer is: √t

jagged grotto
#

Uh

#

Where's the square root coming from now

#

And why is it *2

#

And not .5*1/2

kindred swift
#

t^1/2 is the 2nd root of t.

#

Aka the square root

kindred swift
#

Recall the power rule of integration: it doesn't involve multiplication only division

jagged grotto
#

That's too much for me